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6p^2+49p+8=0
a = 6; b = 49; c = +8;
Δ = b2-4ac
Δ = 492-4·6·8
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-47}{2*6}=\frac{-96}{12} =-8 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+47}{2*6}=\frac{-2}{12} =-1/6 $
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